document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522123>Question 522123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclist are traveling the same distance at the speeds of 10 km/hr and 15 km/hr If one cyclist takes 40 minutes more to cover the distance, the what distance (in Km) are they traveling ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346714 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let distance be x\r<BR>\n" );
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document.write( "first cyclist rate = x/10<BR>\n" );
document.write( "second cyclist rate = x/15\r<BR>\n" );
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document.write( "difference in time = 40 minutes=> 40/60=>2/3 hour\r<BR>\n" );
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document.write( "x/10-x/15=2/3\r<BR>\n" );
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document.write( "LCD = 30<BR>\n" );
document.write( "multiply equation by 30<BR>\n" );
document.write( "3x-2x=20<BR>\n" );
document.write( "x=20 km is the distance\r<BR>\n" );
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document.write( " </SPAN>\n" );
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