document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522149>Question 522149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You need a 40% alcohol solution. On hand, you have a 650 mL of a 20% alcohol mixture. You also have 90% alcohol mixture. How much of the 90% mixture will you need to add to obtain the desired solution?\r<BR>\n" );
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document.write( "You will need <BR>\n" );
document.write( " mL of the 90% solution <BR>\n" );
document.write( "to obtain <BR>\n" );
document.write( " mL of the desired 40% solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346711 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	--------percent	----------------	quantity									<BR>\n" );
document.write( "Alcohol Type I	20	----------------			650	ml						<BR>\n" );
document.write( "Alcohol type II	90	----------------			x	ml						<BR>\n" );
document.write( "Mixture	40	----------------	650	+	x	ml						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "20*650+90x=40(650+x)<BR>\n" );
document.write( "13000+90x=26000	+40x				<BR>\n" );
document.write( "90x-40x	=26000-(	-13000)				<BR>\n" );
document.write( "50x=13000									<BR>\n" );
document.write( "/50											<BR>\n" );
document.write( "x=	260										<BR>\n" );
document.write( "260	ml		of			Alcohol type II	(90%)			<BR>\n" );
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