document.write( "Question 522145: You need a 85% alcohol solution. On hand, you have a 90 mL of a 25% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?\r
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Algebra.Com's Answer #346707 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "Alcohol Type I 25 ---------------- 90 ml
\n" ); document.write( "Pure alcohol 100 ---------------- x ml
\n" ); document.write( "Mixture 85 ---------------- 90 + x ml
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\n" ); document.write( "25 *90+100x=85( 90+x)
\n" ); document.write( "2250+100x=7650+ 85 x
\n" ); document.write( "100x-85 x = 7650 - -2250
\n" ); document.write( "15 x = 5400
\n" ); document.write( "/ 15
\n" ); document.write( "x = 360
\n" ); document.write( " 360 ml of Pure alcohol
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