document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522115>Question 522115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 32 feet. The length is three times the width. Finf the diagonal. Round to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346692 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 32 feet. The length is three times the width. Finf the diagonal. Round to the nearest tenth.<BR>\n" );
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document.write( "Let w = width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3w = length<BR>\n" );
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document.write( "Because we know the perimeter:<BR>\n" );
document.write( "32 = 2(w + 3w)<BR>\n" );
document.write( "32 = 2(4w)<BR>\n" );
document.write( "16 = 4w<BR>\n" );
document.write( "4 feet = w (width)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Length:<BR>\n" );
document.write( "3w = 3(4) = 12 feet<BR>\n" );
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document.write( "Diagonal, we use the pythagorean theorem:<BR>\n" );
document.write( "Let d = diagonal<BR>\n" );
document.write( "then<BR>\n" );
document.write( "d^2 = 4^2 + 12^2<BR>\n" );
document.write( "d^2 = 16 + 144<BR>\n" );
document.write( "d^2 = 160<BR>\n" );
document.write( "d = 12.6 feet<BR>\n" );
document.write( " </SPAN>\n" );
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