document.write( "Question 519875: Find the equation of a line perpendicular to 4x-3y=12 that passes through the point (2,3). \r
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Algebra.Com's Answer #346673 by lwsshak3(11628)\"\" \"About 
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Find the equation of a line perpendicular to 4x-3y=12 that passes through the point (2,3)
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\n" ); document.write( "Standard form of equation for a straight line: y=mx+b, m=slope, b= y-intercept
\n" ); document.write( "For given equation:
\n" ); document.write( "4x-3y=12
\n" ); document.write( "-3y=-4x+12
\n" ); document.write( "divide by -3
\n" ); document.write( "y=4x/3-3
\n" ); document.write( "slope=4/3
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\n" ); document.write( "For line perpendicular to given equation, slope=-3/4 (negative reciprocal)
\n" ); document.write( "Equation: y=-3x/4+b
\n" ); document.write( "Solving for b using coordinates of given point (2,3)
\n" ); document.write( "3=-3*2/4+b
\n" ); document.write( "b=3+6/4=36/12+18/12=54/12=9/2
\n" ); document.write( "equation: y=-3x/4+9/2
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