document.write( "Question 521991: Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. how old is Peter now? \n" ); document.write( "
Algebra.Com's Answer #346669 by lwsshak3(11628)\"\" \"About 
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Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. how old is Peter now?
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\n" ); document.write( "let x=Peter's age now
\n" ); document.write( "2x/3=Mary's age now
\n" ); document.write( "two years ago, Mary's age=(2x/3)-2=(2x-6)/3
\n" ); document.write( "5 years from now, Peter's age=(x+5)
\n" ); document.write( "..
\n" ); document.write( "((2x-6)/3)/(x+5)=1/2
\n" ); document.write( "(2x-6)/3(x+5)=1/2
\n" ); document.write( "4x-12=3x+15
\n" ); document.write( "x=27
\n" ); document.write( "ans:
\n" ); document.write( "Peter's age now=27
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