document.write( "Question 521991: Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. how old is Peter now? \n" ); document.write( "
Algebra.Com's Answer #346669 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. how old is Peter now? \n" ); document.write( "** \n" ); document.write( "let x=Peter's age now \n" ); document.write( "2x/3=Mary's age now \n" ); document.write( "two years ago, Mary's age=(2x/3)-2=(2x-6)/3 \n" ); document.write( "5 years from now, Peter's age=(x+5) \n" ); document.write( ".. \n" ); document.write( "((2x-6)/3)/(x+5)=1/2 \n" ); document.write( "(2x-6)/3(x+5)=1/2 \n" ); document.write( "4x-12=3x+15 \n" ); document.write( "x=27 \n" ); document.write( "ans: \n" ); document.write( "Peter's age now=27 \n" ); document.write( " |