document.write( "Question 522019: Linda invested her savings in two investment funds. The amount she invested in Fund A was 6000 less than the amount she invested in Fund B. Fund A returned a 8% profit and Fund B returned a 5 % profit. How much did she invest in Fund A, if the total profit from the two funds together was 1340 ?
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Algebra.Com's Answer #346663 by mananth(16946)\"\" \"About 
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Fund B --------------- x--------------5%\r
\n" ); document.write( "\n" ); document.write( "Fund A----------------x-6000----------8%\r
\n" ); document.write( "\n" ); document.write( "Interest = 1340\r
\n" ); document.write( "\n" ); document.write( "The percent has been converted by multiplying the equation by 100\r
\n" ); document.write( "\n" ); document.write( "5x+8(x-6000)= 1340*100\r
\n" ); document.write( "\n" ); document.write( "5x+8x-48000=134000
\n" ); document.write( "13x=134000+48000
\n" ); document.write( "13x=182000
\n" ); document.write( "/13
\n" ); document.write( "x=14000 Fund B\r
\n" ); document.write( "\n" ); document.write( "Fund A - 8000\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "8000*8%+14000*5%=>640+700=1340
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