document.write( "Question 521985: The length of a rectangle is 8 more than 3 times the width, if the perimeter is 64, what are the measurements? The area? \n" ); document.write( "
Algebra.Com's Answer #346642 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 8 more than 3 times the width, if the perimeter is 64, what are the measurements? The area?
\n" ); document.write( "-----
\n" ); document.write( "L = 3W + 8
\n" ); document.write( "---
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "64 = 2(3W+8 + W)
\n" ); document.write( "32 = 4W+8
\n" ); document.write( "4W = 24
\n" ); document.write( "Width = 6
\n" ); document.write( "---
\n" ); document.write( "Then Length = 3*6 + 8 = 26
\n" ); document.write( "----
\n" ); document.write( "Area = L*W
\n" ); document.write( "Area = 6*26 = 156
\n" ); document.write( "=======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" );