document.write( "Question 521985: The length of a rectangle is 8 more than 3 times the width, if the perimeter is 64, what are the measurements? The area? \n" ); document.write( "
Algebra.Com's Answer #346642 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 8 more than 3 times the width, if the perimeter is 64, what are the measurements? The area? \n" ); document.write( "----- \n" ); document.write( "L = 3W + 8 \n" ); document.write( "--- \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "64 = 2(3W+8 + W) \n" ); document.write( "32 = 4W+8 \n" ); document.write( "4W = 24 \n" ); document.write( "Width = 6 \n" ); document.write( "--- \n" ); document.write( "Then Length = 3*6 + 8 = 26 \n" ); document.write( "---- \n" ); document.write( "Area = L*W \n" ); document.write( "Area = 6*26 = 156 \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |