document.write( "Question 521915: Steve has some dimes and quarters worth $4.10. He has 8 fewer dimes than quarters, how many of each coins does he have? \n" ); document.write( "
Algebra.Com's Answer #346635 by mamiya(56)\"\" \"About 
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let d be the number of dimes and q the number of quarters he has.\r
\n" ); document.write( "\n" ); document.write( "So, Steve has $(0.1d + 0.25q)= $4.10
\n" ); document.write( "the number of dimes he has is 8 fewer than the number of quarters.
\n" ); document.write( "so, d=q-8\r
\n" ); document.write( "\n" ); document.write( "from the two equations below, we have the following system:
\n" ); document.write( " 0.25q + 0.1d= 4.10
\n" ); document.write( " q - d = 8
\n" ); document.write( "
\n" ); document.write( " by adding up the first equation and 0.1 time the second equation, we have\r
\n" ); document.write( "\n" ); document.write( " 0.25q + 0.1d + 0.1q - 0.1d = 4.10 + 0.1*8
\n" ); document.write( " 0.35q= 4.9
\n" ); document.write( " q = 4.9/0.35
\n" ); document.write( " = 14\r
\n" ); document.write( "\n" ); document.write( " d = q - 8
\n" ); document.write( " = 14 - 8
\n" ); document.write( " = 6\r
\n" ); document.write( "\n" ); document.write( "so, Steve has 14 quarters and 6 dimes.
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