document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521843>Question 521843</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help with this problem: The measure of two complementary angles are in the ratio 4:1. what is the measure of the smaller angle? THANKS(: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346599 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of two complementary angles are in the ratio 4:1. what is the measure of the smaller angle?<BR>\n" );
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document.write( "4:1 is the same as 4x to x<BR>\n" );
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document.write( "smaller angle: x<BR>\n" );
document.write( "larger angle: 4x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 4x = 90<BR>\n" );
document.write( "5x = 90<BR>\n" );
document.write( "x = 18 degrees (smaller angle)<BR>\n" );
document.write( "4x = 72 degrees (larger angle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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