document.write( "Question 521832: y+5x=0
\n" ); document.write( "x+y=12
\n" ); document.write( "how do you do this? please show all steps
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Algebra.Com's Answer #346594 by umnikmo(75)\"\" \"About 
You can put this solution on YOUR website!
from first eq: y=-5x
\n" ); document.write( "substitute this into second eq:\r
\n" ); document.write( "\n" ); document.write( "x+(-5x)=12
\n" ); document.write( "-4x=12 => x=-3\r
\n" ); document.write( "\n" ); document.write( "y=-5*x=-5*(-3)=15
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