document.write( "Question 521731: amy drove 200 miles at an average speed 10 miles per hour faster than her usual speed. if she completed the trip in 1 hour less time than usual, what is her usual driving speed in miles per hour? \n" ); document.write( "
Algebra.Com's Answer #346572 by mamiya(56)\"\" \"About 
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let x be the usual average speed and t the among of times she usually took to complete the trip. let s be the average speed , t' the among of time she takes now and d the distance.\r
\n" ); document.write( "\n" ); document.write( " s= x + 10 since her average speed now is 10 miles per hour more than her usual speed
\n" ); document.write( " d= 200 miles
\n" ); document.write( " t'= t - 1 since she completed the trip in 1 hour less time usual\r
\n" ); document.write( "\n" ); document.write( "we know that distance= speed x time
\n" ); document.write( "so d= st' and d= xt\r
\n" ); document.write( "\n" ); document.write( "so xt= 200
\n" ); document.write( " (x+10)(t-1)=200\r
\n" ); document.write( "\n" ); document.write( " xt=200
\n" ); document.write( " xt - x + 10t -10= 200\r
\n" ); document.write( "\n" ); document.write( " xt=200
\n" ); document.write( " 200 - x + 10t - 10 =200\r
\n" ); document.write( "\n" ); document.write( " xt=200
\n" ); document.write( " 10t - x= 10
\n" ); document.write( "
\n" ); document.write( " x= 10(t - 1)
\n" ); document.write( " xt=200\r
\n" ); document.write( "\n" ); document.write( " x= 10(t-1)
\n" ); document.write( " 10(t-1)*t = 200\r
\n" ); document.write( "\n" ); document.write( " 10t^2 - 10t - 200 =0
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\n" ); document.write( " t^2 - t - 20 =0\r
\n" ); document.write( "\n" ); document.write( "let's call p(x)= t^2 - t - 20 and let's factorize this polynomial.
\n" ); document.write( "the determinant D= (-1)^2 - 4(1)(-20)= 81= (9)^2
\n" ); document.write( " t1= (1+9)/2 = 5
\n" ); document.write( " t2= (1-9)/2 = -4
\n" ); document.write( "so the answers of the equation ( t^2-T-20=0) are 5 and -4, but since t is an among of time , t has to be a positive number, so answer can't be -4 , therefore the answer is 5. \r
\n" ); document.write( "\n" ); document.write( "so t=5
\n" ); document.write( "x=10(t-1)
\n" ); document.write( " = 10(5-1)
\n" ); document.write( " = 40 \r
\n" ); document.write( "\n" ); document.write( "so, her usual driving speed is 40 miles per hour.\r
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