document.write( "Question 521731: amy drove 200 miles at an average speed 10 miles per hour faster than her usual speed. if she completed the trip in 1 hour less time than usual, what is her usual driving speed in miles per hour? \n" ); document.write( "
Algebra.Com's Answer #346572 by mamiya(56)![]() ![]() ![]() You can put this solution on YOUR website! let x be the usual average speed and t the among of times she usually took to complete the trip. let s be the average speed , t' the among of time she takes now and d the distance.\r \n" ); document.write( "\n" ); document.write( " s= x + 10 since her average speed now is 10 miles per hour more than her usual speed \n" ); document.write( " d= 200 miles \n" ); document.write( " t'= t - 1 since she completed the trip in 1 hour less time usual\r \n" ); document.write( "\n" ); document.write( "we know that distance= speed x time \n" ); document.write( "so d= st' and d= xt\r \n" ); document.write( "\n" ); document.write( "so xt= 200 \n" ); document.write( " (x+10)(t-1)=200\r \n" ); document.write( "\n" ); document.write( " xt=200 \n" ); document.write( " xt - x + 10t -10= 200\r \n" ); document.write( "\n" ); document.write( " xt=200 \n" ); document.write( " 200 - x + 10t - 10 =200\r \n" ); document.write( "\n" ); document.write( " xt=200 \n" ); document.write( " 10t - x= 10 \n" ); document.write( " \n" ); document.write( " x= 10(t - 1) \n" ); document.write( " xt=200\r \n" ); document.write( "\n" ); document.write( " x= 10(t-1) \n" ); document.write( " 10(t-1)*t = 200\r \n" ); document.write( "\n" ); document.write( " 10t^2 - 10t - 200 =0 \n" ); document.write( " \n" ); document.write( " t^2 - t - 20 =0\r \n" ); document.write( "\n" ); document.write( "let's call p(x)= t^2 - t - 20 and let's factorize this polynomial. \n" ); document.write( "the determinant D= (-1)^2 - 4(1)(-20)= 81= (9)^2 \n" ); document.write( " t1= (1+9)/2 = 5 \n" ); document.write( " t2= (1-9)/2 = -4 \n" ); document.write( "so the answers of the equation ( t^2-T-20=0) are 5 and -4, but since t is an among of time , t has to be a positive number, so answer can't be -4 , therefore the answer is 5. \r \n" ); document.write( "\n" ); document.write( "so t=5 \n" ); document.write( "x=10(t-1) \n" ); document.write( " = 10(5-1) \n" ); document.write( " = 40 \r \n" ); document.write( "\n" ); document.write( "so, her usual driving speed is 40 miles per hour.\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |