document.write( "Question 521731: amy drove 200 miles at an average speed 10 miles per hour faster than her usual speed. if she completed the trip in 1 hour less time than usual, what is her usual driving speed in miles per hour? \n" ); document.write( "
Algebra.Com's Answer #346568 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! amy drove 200 miles at an average speed 10 miles per hour faster than her usual speed. if she completed the trip in 1 hour less time than usual, what is her usual driving speed in miles per hour? \n" ); document.write( "--- \n" ); document.write( "Early trip DATA: \n" ); document.write( "distance = 200 miles; rate = r+10 mph ; time = 200/(r+10) hrs \n" ); document.write( "------------------------ \n" ); document.write( "Later trip DATA: \n" ); document.write( "distance = 200 miles : rate = r mph ; time = 200/r hrs \n" ); document.write( "------------------------- \n" ); document.write( "Equation: \n" ); document.write( "early time - later time = 1 hr \n" ); document.write( "--- \n" ); document.write( "200/r - 200/(r+10) = 1 hr. \n" ); document.write( "--- \n" ); document.write( "200(r+10) - 200r = r(r+10) \n" ); document.write( "---- \n" ); document.write( "200*10 = r^2+10r \n" ); document.write( "---- \n" ); document.write( "r^2 + 10r - 2000 = 0 \n" ); document.write( "---- \n" ); document.write( "(r-40)(r+50) = 0 \n" ); document.write( "====================== \n" ); document.write( "Positive Solution: \n" ); document.write( "rate = 40 mph \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " \n" ); document.write( " |