document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521629>Question 521629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in triangle ABC, line AB is 9 cm shorter than line AC, while line BC is 3 cm longer than line AC. If the perimeter of the triangle is 48 cm, find the lenghts of the 3 sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346552 by </B><A HREF=/tutors/aboutme.mpl?userid=jlshires><B>jlshires(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jlshires><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since all the sides are being compared to AC, AC is your x.\r<BR>\n" );
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document.write( "Let AC = x<BR>\n" );
document.write( "Let AB = 9 cm shorter than AC = x-9<BR>\n" );
document.write( "Let BC = 3 cm longer than AC = x+3\r<BR>\n" );
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document.write( "The perimeter of a triangle is all of the sides added, therefore AC + AB + BC<BR>\n" );
document.write( "the perimeter is 48\r<BR>\n" );
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document.write( "AC + AB + BC = 48 substitute in your formulas for the sides<BR>\n" );
document.write( "x + (x-9) + (x+3) = 48\r<BR>\n" );
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document.write( "factor out the addition signs to get rid of the parentheses\r<BR>\n" );
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document.write( "x+x-9+x+3=48\r<BR>\n" );
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document.write( "combine like symbols\r<BR>\n" );
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document.write( "3x - 6 = 48\r<BR>\n" );
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document.write( "add 6 to both sides\r<BR>\n" );
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document.write( "3x = 54\r<BR>\n" );
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document.write( "divide both sides by 3\r<BR>\n" );
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document.write( "x = 18\r<BR>\n" );
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document.write( "Put 18 back into your original formulas to find out the lengths of all three sides:\r<BR>\n" );
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document.write( "Let AC = x = 18<BR>\n" );
document.write( "Let AB = 9 cm shorter than AC = x-9 = 18-9 = 9<BR>\n" );
document.write( "Let BC = 3 cm longer than AC = x+3 = 18+3 = 21\r<BR>\n" );
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document.write( "the sides are 18, 9, and 21<BR>\n" );
document.write( " </SPAN>\n" );
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