document.write( "Question 521603: Susan is six years older than Mary. She is also twice as old as Mary was when Susan was as old as Mary is now. How old is each now?
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Algebra.Com's Answer #346550 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let

represent Susan's age now. Let

represent Mary's age now.\r
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\n" ); document.write( "\n" ); document.write( "We know that\r
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\n" ); document.write( "\n" ); document.write( "Susan was as old as Mary is now 6 years ago, so Susan's age when she was as old as Mary is now is

which we can see is the same as

. 6 years ago Mary was

. So Susan's age 6 years ago was twice Mary's age 6 years ago:\r
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\n" ); document.write( "\n" ); document.write( "Solve for

, then calculate

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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