document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521595>Question 521595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains made the same 350-mile run. Since one train traveled 15 mph faster than the other, it arrived 3 hours earlier. Find the speed of each train.\r<BR>\n" );
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document.write( "This is how I set it up, but I'm lost after that\r<BR>\n" );
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document.write( "350/x +3= 350/x-15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346547 by </B><A HREF=/tutors/aboutme.mpl?userid=umnikmo><B>umnikmo(75)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umnikmo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V1=V2+15<BR>\n" );
document.write( "t1=350/V1=350/(V2+15)<BR>\n" );
document.write( "t2=350/V2\r<BR>\n" );
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document.write( "t1+3=t2<BR>\n" );
document.write( "350/(V2+15)+3=350/V2\r<BR>\n" );
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document.write( "multiplying everything by (V2+15)V2\r<BR>\n" );
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document.write( "350V2+3V2^2+45V2=350V2+5250<BR>\n" );
document.write( "3V2^2+45V2^2-5250=0\r<BR>\n" );
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document.write( "Solution is : V2=35mph\r<BR>\n" );
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document.write( "V1=35+15=50mph\r<BR>\n" );
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document.write( " </SPAN>\n" );
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