document.write( "Question 521574: Three times the complement of an angle is 30 degrees less than the angle
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Algebra.Com's Answer #346532 by MathLover1(20850) $\"\"$ $\"About$

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let's the complement angles be $\"alpha\"$ and $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "by definition of complement angles $\"alpha%2Bbeta=90\"$ \r
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\n" ); document.write( "\n" ); document.write( "Three times the complement of an angle is 30 degrees less than the angle:\r
\n" ); document.write( "\n" ); document.write( " $\"3%2Abeta+%2B30=alpha\"$ .... plug it in $\"alpha%2Bbeta=90\"$ and solve for $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%2Abeta+%2B30%2Bbeta=90\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4%2Abeta+=90-30\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4%2Abeta+=60\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta+=60%2F4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta+=15\"$ ....now find $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=3%2Abeta+%2B30\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=3%2A15+%2B30\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=45+%2B30\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=75\"$ \r
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