document.write( "Question 521455: 5x+y= 20
\n" ); document.write( "5x+5y= 15
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Algebra.Com's Answer #346490 by umnikmo(75)\"\" \"About 
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5x+y=20 (1)
\n" ); document.write( "5x+5y=15 (2)\r
\n" ); document.write( "\n" ); document.write( "(2)-(1):
\n" ); document.write( "4y=-5 => y=-5/4\r
\n" ); document.write( "\n" ); document.write( "from (1):\r
\n" ); document.write( "\n" ); document.write( "x=(20-y)/5 = (20+5/4)/5 = 17/4 = 4 1/4\r
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\n" ); document.write( "\n" ); document.write( "Ans:
\n" ); document.write( "X= 4 1/4
\n" ); document.write( "Y= -(1 1/4)
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