document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521467>Question 521467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given AL=SK how do you prove AS=LK <BR>\n" );
document.write( "on a line segment of ALSK </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346488 by </B><A HREF=/tutors/aboutme.mpl?userid=umnikmo><B>umnikmo(75)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umnikmo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> on a line segment ALSK, lets call distance A to L - D, same distance in L to K - D. lets call distance L-S as X.\r<BR>\n" );
document.write( "\n" );
document.write( "now, distance from A to S is AL+LS = D+X; distance from L to K is LS+SK = X+D;<BR>\n" );
document.write( "so AS = D+X = X+D = LK. <BR>\n" );
document.write( "Proven </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );