document.write( "Question 521220: Leticia is 21 years older than Kate, in 2 years, Leticia will be twice as old as Kate. Find Leticia's and Katie's current age? \n" ); document.write( "
Algebra.Com's Answer #346452 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Leticia = l \n" ); document.write( "Present age of Kate = k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Leticia is 21 years older than Kate \n" ); document.write( "l=k+21................(1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 2 years, \n" ); document.write( "Leticia's age will be = l + 2 \n" ); document.write( "Kate's age will be = k + 2 \n" ); document.write( "Then, \n" ); document.write( "Leticia will be twice as old as Kate. \n" ); document.write( "l + 2 = 2 (k + 2) \n" ); document.write( "l + 2 = 2k + 4 \n" ); document.write( "l = 2k + 4 - 2 \n" ); document.write( "l = 2k + 2 ..................(2)\r \n" ); document.write( "\n" ); document.write( "Put the value of l from (1) to (2) \n" ); document.write( "k + 21 = 2k + 2 \n" ); document.write( "k - 2k = 2 - 21 \n" ); document.write( "-k = -19 \n" ); document.write( "Multiply by -1 both sides \n" ); document.write( "k = 19 \n" ); document.write( "Put the value of k in (1) \n" ); document.write( "l=k+21 \n" ); document.write( "l=19+21 \n" ); document.write( "l = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Leticia = l = 40 years old \n" ); document.write( "Present age of Kate = k = 19 years old \n" ); document.write( " \n" ); document.write( " |