document.write( "Question 521371: the father was 8 times older than his doughter 4 years ago,in twenty years time the father wil be twice the age of the doughter. 1)how old is the father now? 2)how old wl be the doughter in 30 years time?
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Algebra.Com's Answer #346449 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Father = f \n" ); document.write( "Present age of Daughter = d\r \n" ); document.write( "\n" ); document.write( "4 years ago \n" ); document.write( "Age of father = f-4 \n" ); document.write( "Age of daughter = d-4 \n" ); document.write( "Then \n" ); document.write( "The father was 8 times older than his daughter \n" ); document.write( "f-4=8(d-4) \n" ); document.write( "f-4=8d-32 \n" ); document.write( "f=8d-32+4 \n" ); document.write( "f=8d-28......................(1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In twenty years time \n" ); document.write( "Age of father will be = f + 20 \n" ); document.write( "Age of daughter will be = d+ 20 \n" ); document.write( "Then \n" ); document.write( "father will be twice the age of the daughter. \n" ); document.write( "f+20=2(d+20) \n" ); document.write( "f+20=2d+40 \n" ); document.write( "f=2d+40-20 \n" ); document.write( "f=2d+20.......................(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in the value of f from (1) to (2) \n" ); document.write( "8d-28=2d+20 \n" ); document.write( "8d-2d=20+28 \n" ); document.write( "6d=48 \n" ); document.write( "6d/6=48/6 \n" ); document.write( "d=8 \n" ); document.write( "Put the value of d in (1) \n" ); document.write( "f=8d-28 \n" ); document.write( "f=8(8)-28 \n" ); document.write( "f=64-28 \n" ); document.write( "f=36\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Father = f = 36 years old \n" ); document.write( "Present age of Daughter = d = 8 years old \n" ); document.write( "Daughter will be 38 years old after 30 years. \n" ); document.write( " |