document.write( "Question 51912: Kandi has $2.65 in nickels and dimes. If she has 40 coins in all, how many nickels does she have? \n" ); document.write( "

Algebra.Com's Answer #34644 by funmath(2933) $\"\"$ $\"About$

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If N is nickles and D is dimes then N+D=40 because Kandi has 40 coins.
\n" ); document.write( "If we solve this equation for N we get:
\n" ); document.write( "N+D-N=40-N
\n" ); document.write( "D=40-N
\n" ); document.write( "So the number of dimes we have is 40-N
\n" ); document.write( "and the number of nickles we have is N\r
\n" ); document.write( "\n" ); document.write( "The amount of money we have is equal to the worth of the coin times the number of coins. I like to solve these equations in terms of cents rather than dollars because it eliminates the decimals.\r
\n" ); document.write( "\n" ); document.write( "The amount of money we have in dimes is 10(40-N).
\n" ); document.write( "The amount of money we have in nickles is 5N.
\n" ); document.write( "The total amount of money we have is 265 (in cents).\r
\n" ); document.write( "\n" ); document.write( "Therefore, (the amount of money in dimes)+(the amount of money in nickles)=(total) becomes:
\n" ); document.write( "10(40-N)+5N=265
\n" ); document.write( "400-10N+5N=265
\n" ); document.write( "400-5N=265
\n" ); document.write( "-400+400-5N=265-400
\n" ); document.write( "-5N=-135
\n" ); document.write( "-5N/-5=-135/-5
\n" ); document.write( "N=27
\n" ); document.write( "Thus, Kandi had 27 nickels. \n" ); document.write( "

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