document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521318>Question 521318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I am working on the problem 9x + 3y - 5 = 0 and 3x + y = 5/3. It's asking to solve the system of equations using substitution. I don't get what I have to plug in to get the answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346422 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9	x	+	3	y	=	5	.............1				<BR>\n" );
document.write( "1	y	=	1.67		-3	x	---------2				<BR>\n" );
document.write( "/	1	=									<BR>\n" );
document.write( "	y	=	1.67		-3	x					<BR>\n" );
document.write( "Substitute y in 		(1)									<BR>\n" );
document.write( "9x+3(1.67-3x)=	5<BR>\n" );
document.write( "9x+5+-9	x=5			<BR>\n" );
document.write( "9x-9x=5	-5				<BR>\n" );
document.write( "0x=0\r<BR>\n" );
document.write( "\n" );
document.write( "There is no solution to this system\r<BR>\n" );
document.write( "\n" );
document.write( "they are parallel lines with different  y intercepts	slopes are same							<BR>\n" );
document.write( " </SPAN>\n" );
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