document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=521237>Question 521237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In comparing two local well-known DJs for this year’s street dance, you see two good choices.  DJ Joe charges $100 for each hour of play time.  DJ Dan charges a fee of $150, plus $75 an hour of play time.\r<BR>\n" );
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document.write( "a.	For two hours of play time, what would be the charge for each and who would charge the lesser amount?<BR>\n" );
document.write( "b.	For eight hours of play time, what would be the charge for each and who would charge the lesser amount?<BR>\n" );
document.write( "c.	For how many hours would DJ Joe provide the better deal?  Express your answer as an inequality.  Explain how you found your answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346386 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of 		hours				<BR>\n" );
document.write( "DJ Joe			0	+	100.00	x<BR>\n" );
document.write( "DJ Dan			150	+	75.00	x\r<BR>\n" );
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document.write( "For 2 hours<BR>\n" );
document.write( "DJ Joe	0	+	100.00	*	2		=		200		<BR>\n" );
document.write( "DJ Dan	150	+	75.00	*	2		=		300\r<BR>\n" );
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document.write( "For 8 hours\r<BR>\n" );
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document.write( "DJ Joe	0	+	100.00	*	8		=		800<BR>\n" );
document.write( "DJ Dan	150	+	75.00	*	8		=		750\r<BR>\n" );
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document.write( "Better deal\r<BR>\n" );
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document.write( "DJ Joe	<	DJ Dan								<BR>\n" );
document.write( "0	+	100.00	x 			<	150	+	75.00	x <BR>\n" );
document.write( "0	+	100.00	x 			<	150	+	75.00	x <BR>\n" );
document.write( "0	-	150				<	75	x	-100	x<BR>\n" );
document.write( "-150	<	-25	x 							<BR>\n" );
document.write( "6	>	x								<BR>\n" );
document.write( "x should be less than			6	hours						\r<BR>\n" );
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document.write( "		<BR>\n" );
document.write( " </SPAN>\n" );
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