document.write( "Question 520818: Solve for a using the addition and multiplication principles: 14-6a= -2a+3\r
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Algebra.Com's Answer #346332 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"14-6a=-2a%2B3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-6a=-2a%2B3-14\" Subtract \"14\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-6a%2B2a=3-14\" Add \"2a\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4a=3-14\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-4a=-11\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%28-11%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=11%2F4\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"a=11%2F4\" \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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