document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520997>Question 520997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: 28+5a-12a^2=0<BR>\n" );
document.write( "Using factoring and property of 0 we are suppose to solve this problem. I can factor but when I get the finding the answer I get stuck </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346298 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve: 28+5a-12a^2=0<BR>\n" );
document.write( "**<BR>\n" );
document.write( "First thing to do is rewrite the equation in decending order<BR>\n" );
document.write( "-12a^2+5a+28=0<BR>\n" );
document.write( "Get rid of a negative lead coefficient by multiplying both sides of equation by -1<BR>\n" );
document.write( "12a^2-5a-28=0<BR>\n" );
document.write( "This doesn't look very easy to factor, so consider using the quadratic formula to solve.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If you are good at factoring, the answers are: <BR>\n" );
document.write( "(3a+4)(4a-7)=0<BR>\n" );
document.write( "a=-4/3<BR>\n" );
document.write( "or<BR>\n" );
document.write( "a=7/4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );