document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520931>Question 520931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2y+3)^2-7=0 using the square root property.<BR>\n" );
document.write( "Sqrt (3-x) ) -7=0<BR>\n" );
document.write( "Sqrt (x+5) )= 7-x<BR>\n" );
document.write( "Simplify 2 sqrt (75))- 5 sqrt (27))- sqrt (48)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346286 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2y+3)^2-7=0 using the square root property.<BR>\n" );
document.write( "(2y+3)^2=7 <BR>\n" );
document.write( "2y+3=+-sqrt(7)<BR>\n" );
document.write( "2y=-3+-sqrt(7)<BR>\n" );
document.write( "y=(-3+-sqrt(7))/2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );