Algebra.Com's Answer #346213 by MathLover1(20850)  You can put this solution on YOUR website! \n" );
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document.write( " Solved by pluggable solver: FIND a line by slope and one point | \n" );
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document.write( " What we know about the line whose equation we are trying to find out: \n" );
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document.write( " - it goes through point (2, -5)
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document.write( " - it has a slope of 3
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document.write( " First, let's draw a diagram of the coordinate system with point (2, -5) plotted with a little blue dot: \n" );
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document.write( " Write this down: the formula for the equation, given point and intercept a, is \n" );
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document.write( " (see a paragraph below explaining why this formula is correct) \n" );
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document.write( " Given that a=3, and , we have the equation of the line: \n" );
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document.write( " Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point ( , ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for ( , ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: . \n" );
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document.write( " Here's the graph: \n" );
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document.write( "The other format for straight-line equations is called the \"point-slope\" form. For this one, they give you a point ( , ) and a slope , and have you plug it into this formula:\r \n" );
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document.write( "so, you will have:\r \n" );
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document.write( "and slope-intercept form is:\r \n" );
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