document.write( "Question 520238: John is 10 years older than Chris. In 2 years John will be twice as old as Chris. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #346199 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of John = j
\n" ); document.write( "Present age of Chris = c\r
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\n" ); document.write( "\n" ); document.write( "John is 10 years older than Chris.
\n" ); document.write( "j=c+10 ..........(1)
\n" ); document.write( "In 2 years
\n" ); document.write( "John will be = j + 2
\n" ); document.write( "Chris will be = c + 2
\n" ); document.write( "Then,
\n" ); document.write( "John will be twice as old as Chris.
\n" ); document.write( "j + 2 = 2(c + 2)
\n" ); document.write( "j + 2 = 2c + 4
\n" ); document.write( "j = 2c + 4 - 2
\n" ); document.write( "J = 2c + 2 .............(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of j from (1) to (2)\r
\n" ); document.write( "\n" ); document.write( "c+10 = 2c + 2 .............(2)
\n" ); document.write( "c-2c=2-10
\n" ); document.write( "-c=-8
\n" ); document.write( "Multiply by -1 both sides
\n" ); document.write( "c=8
\n" ); document.write( "Put the value of c in (1)\r
\n" ); document.write( "\n" ); document.write( "j = 8 + 10
\n" ); document.write( "j = 18\r
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\n" ); document.write( "\n" ); document.write( "Present age of John = j = 18 years old
\n" ); document.write( "Present age of Chris = c = 8 years old
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