document.write( "Question 520695: A businessman borrowed from two moneylenders a sum of rs 2000.for 1 loan the rate of simple interest was 8% Pa and the other was 6 % pa he paid total interest of rs 136 for one year .find the sum borrowed on each rate by him ? \n" ); document.write( "

Algebra.Com's Answer #346188 by Maths68(1474) $\"\"$ $\"About$

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Amount taken at 8% = x
\n" ); document.write( "Amount taken at 6% = 2000-x
\n" ); document.write( "Total interest paid = 136\r
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\n" ); document.write( "\n" ); document.write( "Amount taken * interest rate + Amount taken * interest rate = Total interest paid
\n" ); document.write( "x*8% + (2000-x)*6% = 136
\n" ); document.write( "x*8/100 + (2000-x)*6/100 = 136
\n" ); document.write( "Multiply by 100 both sides
\n" ); document.write( "x*8 + (2000-x)*6 = 136 * 100
\n" ); document.write( "8x + 12000-6x=13600
\n" ); document.write( "8x - 6x=13600-12000
\n" ); document.write( "2x=1600
\n" ); document.write( "2x/2=1600/2
\n" ); document.write( "x=800\r
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\n" ); document.write( "\n" ); document.write( "Amount taken at 8% = x = 800
\n" ); document.write( "Amount taken at 6% = 2000-x = 2000-800 = 1200\r
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\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "800 * 8/100 + 1200 * 6/100 = 136
\n" ); document.write( "8*8 + 12*6 = 136
\n" ); document.write( "64+72 = 136
\n" ); document.write( "136=136 \n" ); document.write( "

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