document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520699>Question 520699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pratap Puri rowed 18 miles down the Delaware River in 2 hours, but the return trip took him 4 1/2 hours. Find the rate Pratap can row in still water, and find the rate of the current.<BR>\n" );
document.write( " Let x= rate Pratap can row in still water and y = rate of the current \r<BR>\n" );
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document.write( "Downstream x+y<BR>\n" );
document.write( "Upstream   x-y\r<BR>\n" );
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document.write( "I think the first one is 2x+y=18\r<BR>\n" );
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document.write( "I can't figure out the second part. Something like:<BR>\n" );
document.write( "x=y-4.5.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346186 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> boat  	speed	=x	mph					<BR>\n" );
document.write( "current  	speed	=y	mph					<BR>\n" );
document.write( "against current x-y		4.50	hours					<BR>\n" );
document.write( "With current x+y		2.00	hours					<BR>\n" );
document.write( "								<BR>\n" );
document.write( "Distance = same=		18	miles					<BR>\n" );
document.write( "t=d/r								<BR>\n" );
document.write( "18	/	(	x	-	y	)=	4.50	<BR>\n" );
document.write( "4.5	(	x	-	y	)	=	18.00	<BR>\n" );
document.write( "4.5	x		-4.5	y	=	18	....................1	<BR>\n" );
document.write( "18	/	(	x	+	y	)=	2.00	<BR>\n" );
document.write( "2.00	(	x	+	y	)	=	18	<BR>\n" );
document.write( "2.00	x	+	2.00	y	=	18	...............2	<BR>\n" );
document.write( "Multiply (1) by 	2.00							<BR>\n" );
document.write( "Multiply (2) by	4.50							<BR>\n" );
document.write( "we get								<BR>\n" );
document.write( "9	x	+	-9	y	=	36		<BR>\n" );
document.write( "9	x	+	9	y	=	81		<BR>\n" );
document.write( "18	x	=	117					<BR>\n" );
document.write( "/	18							<BR>\n" );
document.write( "x 	=	6.5	mph					<BR>\n" );
document.write( "								<BR>\n" );
document.write( "plug value of x in (1)								<BR>\n" );
document.write( "4.5	x		-4.5	y	=	18		<BR>\n" );
document.write( "29.25			-4.5	y	=	18		<BR>\n" );
document.write( "-4.5	y	=	18	-29.25				<BR>\n" );
document.write( "-4.5	y	=	-11.25					<BR>\n" );
document.write( "y=	2.5	mph	<BR>\n" );
document.write( "boat  	6.5	mph					<BR>\n" );
document.write( "current  	2.5	mph\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca					<BR>\n" );
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