document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=518018>Question 518018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve for each of these logs:<BR>\n" );
document.write( "4^ln(3x+2) = 13<BR>\n" );
document.write( "12^e0.03x = 15^e0.01x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346178 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how to solve for each of these logs:<BR>\n" );
document.write( "4^ln(3x+2) = 13<BR>\n" );
document.write( "12^e0.03x = 15^e0.01x<BR>\n" );
document.write( "**<BR>\n" );
document.write( "4^ln(3x+2) = 13<BR>\n" );
document.write( "take log of both sides<BR>\n" );
document.write( "ln(3x+2)ln4=ln13<BR>\n" );
document.write( "ln(3x+2)=ln13/ln4=1.8502<BR>\n" );
document.write( "convert to exponential form: base(e) raised to log of number(1.8502)=number(3x+2)<BR>\n" );
document.write( "e^1.8502=3x+2=6.3611<BR>\n" );
document.write( "3x=4.3611<BR>\n" );
document.write( "x=4.3611/3=2.1201<BR>\n" );
document.write( "..<BR>\n" );
document.write( "12^e0.03x = 15^e0.01x<BR>\n" );
document.write( "take log of both sides<BR>\n" );
document.write( "e0.03xln12=e0.01xln15<BR>\n" );
document.write( "e0.03x/e0.01x=ln15/ln12=1.0898<BR>\n" );
document.write( "3&#8800;1.0898<BR>\n" );
document.write( "no solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );