document.write( "Question 520672: two investments were made totaling 8800 dollars. for a certain year these investments yielded 1326 dollars in simple intrest. part of the 8800 was ivested at 14% and part at 16%. Find the amount invested in each rate \n" ); document.write( "
Algebra.Com's Answer #346165 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Amount invested at 14% = x \n" ); document.write( "Amount invested at 16% = 8800-x \n" ); document.write( "Given \n" ); document.write( "Total interest on both investments = 1326 \r \n" ); document.write( "\n" ); document.write( "14% * (x) + 16% * (8800-x) = 1326 \n" ); document.write( "14/100 * (x) + 16/100 * (8800-x) = 1326 \n" ); document.write( "Multiply by 100 both sides \n" ); document.write( "14 * (x) + 16 * (8800-x) = 1326 * 100 \n" ); document.write( "14x + 140800-16x = 132600 \n" ); document.write( "-2x=132600-140800 \n" ); document.write( "-2x=-8200 \n" ); document.write( "-2x/-2=-8200/-2 \n" ); document.write( "x=4100\r \n" ); document.write( "\n" ); document.write( "Amount invested at 14% = x = 4100 \n" ); document.write( "Amount invested at 16% = 8800-x = 8800-4100 = 4700\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "===== \n" ); document.write( "4100 * 14/100 + 4700 * 16/100 = 1326 \n" ); document.write( "Multiply by 100 both sides \n" ); document.write( "4100*14 + 4700*16 = 132600 \n" ); document.write( "57400+75200=132600 \n" ); document.write( "132600=132600 \n" ); document.write( " |