document.write( "Question 520530: the sum of twice a first number and fives times a second is 97. if the second number is subtracted from fives times the first number the result is 40.find the numbers. \n" ); document.write( "
Algebra.Com's Answer #346098 by mananth(16946)\"\" \"About 
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one number =x
\n" ); document.write( "other =y\r
\n" ); document.write( "\n" ); document.write( "2x+5y=97-----1
\n" ); document.write( "5x-y=40-----2\r
\n" ); document.write( "\n" ); document.write( "multiply (2) by 5
\n" ); document.write( "25x-5y=200
\n" ); document.write( "add this to (1)\r
\n" ); document.write( "\n" ); document.write( "27x=297
\n" ); document.write( "/27
\n" ); document.write( "x=11
\n" ); document.write( "plug x in (1)
\n" ); document.write( "2x+5y=97
\n" ); document.write( "22+5y=97
\n" ); document.write( "5y=75
\n" ); document.write( "/5
\n" ); document.write( "y=15\r
\n" ); document.write( "\n" ); document.write( "11,15 are the numbers\r
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