document.write( "Question 520530: the sum of twice a first number and fives times a second is 97. if the second number is subtracted from fives times the first number the result is 40.find the numbers. \n" ); document.write( "
Algebra.Com's Answer #346098 by mananth(16946) You can put this solution on YOUR website! one number =x \n" ); document.write( "other =y\r \n" ); document.write( "\n" ); document.write( "2x+5y=97-----1 \n" ); document.write( "5x-y=40-----2\r \n" ); document.write( "\n" ); document.write( "multiply (2) by 5 \n" ); document.write( "25x-5y=200 \n" ); document.write( "add this to (1)\r \n" ); document.write( "\n" ); document.write( "27x=297 \n" ); document.write( "/27 \n" ); document.write( "x=11 \n" ); document.write( "plug x in (1) \n" ); document.write( "2x+5y=97 \n" ); document.write( "22+5y=97 \n" ); document.write( "5y=75 \n" ); document.write( "/5 \n" ); document.write( "y=15\r \n" ); document.write( "\n" ); document.write( "11,15 are the numbers\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |