document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520513>Question 520513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What 3 consecutive integers add up to 5961? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346094 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first number be x, then the next two consecutive numbers can be represented by x+1 and x+2. Now we know that x +(x+1)+(x+2) = 5961\r<BR>\n" );
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document.write( "Simplifying the left side we get 3x+3=5961\r<BR>\n" );
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document.write( "then 3x = 5958<BR>\n" );
document.write( " x = 1986.\r<BR>\n" );
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document.write( "Therefore the 3 consecutive numbers are 1986, 1987, and 1988. </SPAN>\n" );
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