document.write( "Question 51889: In 3 years,alex will be 3 times as old as his sister Precy.A year ago,Alex was 7 times as old as Precy.How old are they now? \n" ); document.write( "
Algebra.Com's Answer #34609 by alka001(14)\"\" \"About 
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Let Precys present age be x yrs
\n" ); document.write( "A year ago her age was (x-1) yrs
\n" ); document.write( "So Alex age was 7(x-1) yrs
\n" ); document.write( "Alex present age is 7(x-1)+1
\n" ); document.write( "In 3 yrs Precys age will be x+3
\n" ); document.write( "In 3 yrs Alex age will be 3(x+3)
\n" ); document.write( "3(x+3)=7(x-1)+1+3
\n" ); document.write( "3x+9=7x-7+4
\n" ); document.write( "3x-7x=-11-9
\n" ); document.write( "-4x=-20
\n" ); document.write( "x=5
\n" ); document.write( "So Precys present age is 5 yrs and Alex present age is 7(5-1)+1=28+1=29 yrs
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