document.write( "Question 520456: How much 20%for solution needs to be added to 60% solution to make 400ml of a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #346073 by stanbon(75887)\"\" \"About 
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How much 20%for solution needs to be added to 60% solution to make 400ml of a 40% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.20x + 0.60(400-x) = 0.40*400
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\n" ); document.write( "Multiply thru by 100:
\n" ); document.write( "20x + 60*400 - 60x = 40*400
\n" ); document.write( "-40x = -20*400
\n" ); document.write( "x = 200 ml (amt. of 20% solution needed)
\n" ); document.write( "400-x = 200 ml (amt. of 60% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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