document.write( "Question 520456: How much 20%for solution needs to be added to 60% solution to make 400ml of a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #346073 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much 20%for solution needs to be added to 60% solution to make 400ml of a 40% solution? \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.20x + 0.60(400-x) = 0.40*400 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100: \n" ); document.write( "20x + 60*400 - 60x = 40*400 \n" ); document.write( "-40x = -20*400 \n" ); document.write( "x = 200 ml (amt. of 20% solution needed) \n" ); document.write( "400-x = 200 ml (amt. of 60% solution needed) \n" ); document.write( "============================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " \n" ); document.write( " |