document.write( "Question 51877: -2x+x^2-15 \n" ); document.write( "
Algebra.Com's Answer #34606 by tutorcecilia(2152)\"\" \"About 
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-2x+x^2-15
\n" ); document.write( "x^2-2x-15 [Factor]
\n" ); document.write( "(x-5)(x+3)
\n" ); document.write( "x-5=0
\n" ); document.write( "x=5
\n" ); document.write( "or
\n" ); document.write( "x+3=0
\n" ); document.write( "x=-3
\n" ); document.write( ".
\n" ); document.write( "So, x = {5, -3]
\n" ); document.write( ".
\n" ); document.write( "Check by plugging either value back into the original equation.
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