document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520336>Question 520336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average number of turkeys per flock in Kennebec County is 38 with a standard deviation of 4.\r<BR>\n" );
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document.write( "a.) What size flock would have a z score of -1.5?\r<BR>\n" );
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document.write( "b.) What percent of flocks would be expected to be smaller than b.)?\r<BR>\n" );
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document.write( "I can't tell if I need to use the Z-Score Table in my Statistics book for a.) or if I need to use a formula?\r<BR>\n" );
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document.write( "Thanks in advance!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346023 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You don't need a table to find the z-score for a). You could use the formula but you don't have to either. A z-score of -1.5 means 1.5 standard deviations below the mean, or 1.5(4) = 6 below the mean. The size of the flock corresponding to z = -1.5 would be 38-6 = 32.\r<BR>\n" );
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document.write( "For part b), use a calculator and the normal cdf function. </SPAN>\n" );
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