document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520174>Question 520174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the speed of a boat in still water is 10 mph. if it travels 30 miles up stream and 30 miles down stream in a total of 10 hours what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345984 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The current adds to the rate going downstream and the current subtracts from the rate going upstream.  Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large r_c\"> represent the speed of the current.  Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\"> represent the time for the upstream trip, hence <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 10\ -\ t\"> is the time for the downstream trip.  Finally, time is equal to distance divided by rate, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{30}{10\ -\ r_c}\ =\ t\">\r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{30}{10\ +\ r_c}\ =\ 10\ -\ t\">\r<BR>\n" );
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document.write( "A little Algebra Music, Maestro:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{30}{10\ +\ r_c}\ -\ 10\ =\ -t\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{-30\ +\ 10(10\ +\ r_c)}{10\ +\ r_c}\ =\ t\">\r<BR>\n" );
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document.write( "Now that we have two things equal to <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\">, set them equal to each other (simplifying in the process)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{70\ +\ 10r_c}{10\ +\ r_c}\ =\ \frac{30}{10\ -\ r_c}\">\r<BR>\n" );
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document.write( "All that is left is to cross multiply, collect terms, and solve the resulting quadratic.  Note:  The quadratic does not factor, so use the quadratic formula and simplify; discard the negative root.  Leave your answer in radical form unless you have been instructed elsewhere to provide a numeric approximation.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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