document.write( "Question 520131: find the equation for the line that is parallel to the line wih the equation (y+2)=1/2 (x-4) passing through the point (1,3) \n" ); document.write( "
Algebra.Com's Answer #345949 by Maths68(1474)\"\" \"About 
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\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "(y+2)=1/2 (x-4)
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "y+2=(1/2)x-4(1/2)
\n" ); document.write( "y+2=(1/2)x-2
\n" ); document.write( "y=(1/2)x-2-2
\n" ); document.write( "y=(1/2)x-4
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=1/2 and b=-4
\n" ); document.write( "Since lines are parallel their slopes will be equal,therefore slope of the required line will be (1/2)
\n" ); document.write( "Now we have a point(1,3) and slope (1/2)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "1/2=(y-3))/(x-1)
\n" ); document.write( "1*(x-1)=2(y-3)
\n" ); document.write( "x-1=2y-6
\n" ); document.write( "x-1+6=2y
\n" ); document.write( "x+5=2y
\n" ); document.write( "2y=x+5
\n" ); document.write( "2y/2=(x+5)/2
\n" ); document.write( "y=(1/2)x+5/2
\n" ); document.write( "Above equation is the Equation of Staright line in the Standard Form.
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