document.write( "Question 520104: How do you write an equation of a line using
\n" ); document.write( "Contains (5,8) and that is perpendicular to the line
\n" ); document.write( "Containing (0,-6) and (1,1)
\n" ); document.write( "

Algebra.Com's Answer #345926 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
x1 y1 x2 y2
\n" ); document.write( "0 -6 1 1
\n" ); document.write( "
\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 1 - -6 )/( 1 - 0 )
\n" ); document.write( "( 7 / 1 )
\n" ); document.write( "m= 7 \r
\n" ); document.write( "\n" ); document.write( "slope of line perpendicular will be negative reciprocal of 7\r
\n" ); document.write( "\n" ); document.write( "-1/7\r
\n" ); document.write( "\n" ); document.write( "m= - 1/ 7
\n" ); document.write( "
\n" ); document.write( "Plug value of the slope and point ( 5 , 8 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "8.00 = - 5/7 + b
\n" ); document.write( "b= 8 - - 5/7
\n" ); document.write( "b= 8 5/ 7
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = - 1/7 x + 61/7
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( "
\n" );