document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=520060>Question 520060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Brooks lacks 7 years from being five times as old as her son.  Six years from now she will lack 3 years from being 3 times as old as her son is  then.  Find each of their ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345921 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Son = x years<BR>\n" );
document.write( "Mrs. Brooks 5x-7\r<BR>\n" );
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document.write( "after 6 years<BR>\n" );
document.write( "son = x-6<BR>\n" );
document.write( "Mrs. Brooks = 5x-7-6=>5x-13\r<BR>\n" );
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document.write( "5x-13=3x-3<BR>\n" );
document.write( "5x-3x=13-3<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x=5  son's age<BR>\n" );
document.write( "Mrs. Brook's age =5x-7=> 5*5-7=18 years\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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