document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51874>Question 51874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> help with this problem please...<BR>\n" );
document.write( "   0.4z-0.15=0.65-0.3(6-2z) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34592 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's first expand the right side to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.4z-.15=.65-1.8%2B.6z ALIGN=MIDDLE  ALT=\".4z-.15=.65-1.8%2B.6z\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.4z-.15=-1.15%2B.6z ALIGN=MIDDLE  ALT=\".4z-.15=-1.15%2B.6z\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Subtracting .4z from both sides gives us <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-.15=-1.15%2B.2z ALIGN=MIDDLE  ALT=\"-.15=-1.15%2B.2z\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then adding 1.15 to both sides gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1=.2z ALIGN=MIDDLE  ALT=\"1=.2z\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now we just divide both sides by .2 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5=z ALIGN=MIDDLE  ALT=\"5=z\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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