document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519929>Question 519929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you graph 2log10x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345910 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do you graph 2log10x<BR>\n" );
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document.write( "Start with the basic log x function where the curve starts from the y=axis ,an asymptote, and crosses the x-axis when x=1, that is, y>0 when x>1, and y<0 when 0 < x < 1.<BR>\n" );
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document.write( "log10x=log10+logx=1+logx<BR>\n" );
document.write( "so, we bump the basic log curve one unit up<BR>\n" );
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document.write( "2log10x<BR>\n" );
document.write( "2 is just a multiplier which makes the slope of the final curve steeper\r<BR>\n" );
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document.write( "Comment: don't give me too much credit for figuring this out because I have a graphing program on my computer which showed me exactly what I described above. </SPAN>\n" );
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