document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516813>Question 516813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time graphing this type of problem.  I have the following:\r<BR>\n" );
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document.write( "(x + 3)^2 / 16 + (y - 2)^2 /36 = 1\r<BR>\n" );
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document.write( "I have the following\r<BR>\n" );
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document.write( "(x + 3)^2 / 4^2 + (y - 2 )^2 / 6^2 = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345906 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. (x + 3)^2 / 16 + (y - 2)^2 /36 = 1 <BR>\n" );
document.write( "2. (x + 3)^2 / 4^2 + (y - 2 )^2 / 6^2 = 1<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Both of these equations are ellipses with vertical major axis of the standard form:<BR>\n" );
document.write( "(x-h)^2/b^2+(y-k)^2/a^2=1, a>b, with (h,k) being the (x,y) coordinates of the center.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(note: If the denominator under the x-term was greater than the denominator under the y-term, the ellipse would have a horizontal major axis, and the standard form would be:<BR>\n" );
document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1)<BR>\n" );
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document.write( "For equation 1.<BR>\n" );
document.write( "center: (-3,2)<BR>\n" );
document.write( "a^2=36<BR>\n" );
document.write( "a=&#8730;36=6<BR>\n" );
document.write( "length of vertical major axis=2a=12<BR>\n" );
document.write( "vertices(end-points of major axis): (-3,2±a)=(-3,2±6)=(-3,8) and (-3,-4)<BR>\n" );
document.write( "b^2=16<BR>\n" );
document.write( "b=&#8730;16=4<BR>\n" );
document.write( "length of minor axis=2b=8<BR>\n" );
document.write( "end-points of minor axis: (-3±b,2)=(-3±4,2)=(-7,2) and (1,2)<BR>\n" );
document.write( "Foci<BR>\n" );
document.write( "c^2=a^2-b^2=36-16=20<BR>\n" );
document.write( "c=&#8730;20&#8776;4.47<BR>\n" );
document.write( "foci=(-3,2±c)=(-3,2±4.47)=(-3,6.47) and (-3,-2.27)<BR>\n" );
document.write( "You now have all the coordinates you need to graph equation 1.<BR>\n" );
document.write( "I will leave it up to you to use the same procedure to find the coordinates you need to graph equation 2.   </SPAN>\n" );
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