document.write( "Question 519767: Question: How many ways can 3 students be placed in a row of 5 desk?\r
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document.write( "I tried the standard way, like if you had 5 students in 5 desk, you do 5x4x3x2x1, but I didn't get how to do this problem. \n" );
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Algebra.Com's Answer #345892 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! First Student can be placed = 5 ways \n" ); document.write( "1 desk is occupied 2nd student can be placed on 4 remaing desks = 4 ways \n" ); document.write( "2 desks are occupied 3rd student can be placed on 3 remaing desks = 3 ways\r \n" ); document.write( "\n" ); document.write( "Total Number of ways = 5 * 4 * 3 \n" ); document.write( "Total Number of ways = 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the formula\r \n" ); document.write( "\n" ); document.write( "nPr = n!/(n-r)! \n" ); document.write( "Here we have \n" ); document.write( "n=5 \n" ); document.write( "r=3 \n" ); document.write( "5P3=5!/(5-3)! \n" ); document.write( "5P3=5!/(2)! \n" ); document.write( "5P3=5*4*3*2*1/2*1 \n" ); document.write( "5P3=120/2 \n" ); document.write( "5P3=60 ways.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |