document.write( "Question 519949: how many grams of pure silver must be added to 30 grams of an alloy that is 50% silver to obtain an alloy that is 60% silver? \n" ); document.write( "

Algebra.Com's Answer #345891 by Maths68(1474) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Pure Silver
\n" ); document.write( "Amount = x grams
\n" ); document.write( "Concentration = 1 (Pure Silver)\r
\n" ); document.write( "\n" ); document.write( "Alloy
\n" ); document.write( "Amount = 30 grams
\n" ); document.write( "Concentration = 50% = 0.5\r
\n" ); document.write( "\n" ); document.write( "Final Alloy
\n" ); document.write( "Amount = 30+x grams
\n" ); document.write( "Concentration = 60% = 0.6\r
\n" ); document.write( "\n" ); document.write( "=========================================================
\n" ); document.write( "Pure Sliver Amount * Concentration + Alloy Amount * Concentration = Final Alloy * Final Alloy Concentration\r
\n" ); document.write( "\n" ); document.write( "x*1 + 30*0.5 = (30+x)*0.6
\n" ); document.write( "x+15=18+0.6x
\n" ); document.write( "x-0.6x=18-15
\n" ); document.write( "0.4x=3
\n" ); document.write( "x=3/0.4
\n" ); document.write( "x=7.5 grams\r
\n" ); document.write( "\n" ); document.write( "7.5 grams of pure silver must be added to 30 grams of an alloy that is 50% silver to obtain 37.5 grams of an alloy that is 60% silver?
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