document.write( "Question 519981: x^2+y^2-2xy=1
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document.write( "3x-y=5 \n" );
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Algebra.Com's Answer #345888 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x^2+y^2-2xy=1 \n" ); document.write( "3x-y=5 \n" ); document.write( "y=3x-5\r \n" ); document.write( "\n" ); document.write( "substitute y in x^2+y^2-2xy=1\r \n" ); document.write( "\n" ); document.write( "x^2+(3x-5)^2-2*x*(3x-5)=1 \n" ); document.write( "x^2+9x^2-30x+25-6x^2+10x=1 \n" ); document.write( "4x^2-20x+25=1 \n" ); document.write( "4x^2-20x+24=0 \n" ); document.write( "/4 \n" ); document.write( "x^2-5x+6=0 \n" ); document.write( "x^2-3x-2x+6=0 \n" ); document.write( "x(x-3)-2(x-3)=0 \n" ); document.write( "(x-3)(x-2)=0 \n" ); document.write( "x= 2 OR 3 \n" ); document.write( "Plug x y=3x-5 \n" ); document.write( "When x=2, y = 1 (2,1) \n" ); document.write( "when x=3,y=4. (3,4)\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |