document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519911>Question 519911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the measures of two complimentary angles is 3:7. What is the measure of the larger angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345842 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle = x\r<BR>\n" );
document.write( "\n" );
document.write( "complementary angle = 90-x\r<BR>\n" );
document.write( "\n" );
document.write( "x/(90-x)=3/7\r<BR>\n" );
document.write( "\n" );
document.write( "cross multiply\r<BR>\n" );
document.write( "\n" );
document.write( "7x=3(90-x)\r<BR>\n" );
document.write( "\n" );
document.write( "7x=210-3x<BR>\n" );
document.write( "10x=210<BR>\n" );
document.write( "x=21 deg<BR>\n" );
document.write( "complementary =69 deg\r<BR>\n" );
document.write( "\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );